I indeed baptise you with water unto repentance, but he who is coming after me is mightier than I, whose sandals I am not worthy to carry. He will baptise you with the holy spirit and fire. His winnowing fan is in his hand, and he will thoroughly clean out his threshing floor, and gather his wheat into the barn: but he will burn up the chaff with unquenchable fire. Matthew 3:11-12
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Pipeng : Physics Cyclical Motion : Centripetal Force Physics Homework BETA Game Module

Centripetal Force Physics Games

Description : Physics cyclic motion games : circular motion

Tools In This Module:

BETA : Cyclic : Centripetal Force 01 : Centripetal Force And Acceleration : Beta Physics Homework Game
BETA : Cyclic : Centripetal Force 02 : Conical Pendulum : Beta Physics Homework Game
BETA : Cyclic : Centripetal Force 03 : Balanced Forces On A Banked Curve : Beta Physics Homework Game
BETA : Cyclic : Centripetal Force 04 : Balanced Forces For Vertical Circular Motion : Beta Physics Homework Game
BETA : Cyclic : Centripetal Force 05 : Balanced Forces Kinetic Energy For Vertical Circular Motion : Beta Physics Homework Game
BETA : Cyclic : Centripetal Force 06 : Satellite Orbital Motion : Beta Physics Homework Game


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Module List

BETA : Cyclic : Centripetal Force 01 : Centripetal Force And Acceleration : Beta Physics Homework Game

Description : Centripetal force and acceleration.

Discussion : Centripetal force is the force required to keep a rotating mass in circular motion. See Figure Centripetal Force And Acceleration

a = v2 / r
F = m * v2 / r = m * a
T = 2 * π * r / v
rearranging
r = m * v2 / F = v2 / a
m = F * r / v2
v = 2 * π * r / T
r = T * v / (2 * π)

where

a = acceleration
r = radius
m = mass
v = velocity
T = period of rotation
F = centripetal force

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BETA : Cyclic : Centripetal Force 02 : Conical Pendulum : Beta Physics Homework Game

Description : Conical pendulum.

Discussion : In a conical pendulum the centripetal force and gravity force are balanced by the tension in the pendulum. See Figure Conical Pendulums

Fg = m * g = Ft * cosd(θ)
Fc = m * v2 / r = Ft * sind(θ)
Ft = √(Fc2 + Fg2)
rearranging
m = Fg / g
m = Fc * r / v2
r = m * v2 / Fc
v = √(Fc * r / m)
Ft = Fg / cosd(θ) = Fc / sind(θ)
Fc = Fg * tand(θ)
Fg = Fc / tand(θ)

where

Fc = centripetal force
Fg = gravity force
Ft = tension force
r = radius
m = mass
θ = angle
g = gravity acceleration

The angles are in degrees. You are recommended to use the trigonometry degree functions sind(), cosd(), tand() and atan2d(). Gravity is given here as a constant : g = 9.81 m/s2.

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BETA : Cyclic : Centripetal Force 03 : Balanced Forces On A Banked Curve : Beta Physics Homework Game

Description : Balanced forces for a banked curve.

Discussion : For a banked curve, at a certain velocity the centripetal force, gravity force and reaction force are perfectly balanced. Above or below this velocity tangential friction forces are neccesary to keep the forces balanced. See Figure Banked Curves At the balance condition:

Fg = m * g = Fr * cosd(θ)
Fc = m * v2 / r = Fr * sind(θ)
Fr = √(Fc2 + Fg2)
rearranging
m = Fg / g
m = Fc * r / v2
r = m * v2 / Fc
v = √(Fc * r / m)
Fr = Fg / cosd(θ) = Fc / sind(θ)
Fc = Fg * tand(θ)
Fg = Fc / tand(θ)

where

Fc = centripetal force
Fg = gravity force
Fr = reaction force
r = radius
m = mass
θ = angle
g = gravity acceleration
v = velocity

The reaction force is perpendicular to the the banked surface. The angles are in degrees. You are recommended to use the trigonometry degree functions sind() and cosd().Gravity is given here as a constant : g = 9.81 m/s2.

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BETA : Cyclic : Centripetal Force 04 : Balanced Forces For Vertical Circular Motion : Beta Physics Homework Game

Description : Balanced forces for vertical circular motion.

Discussion : At the balance velocity, the centripetal force and gravity force are equal when the mass is at the top of the circle. Above or below this velocity reaction forces are neccesary to keep the forces balanced. See Figure Vertical Circular Motion At the balance condition:

v = √(r * g)
F = m * g
rearranging
r = v2 / g
m = F / g

where

F = centripetal force = gravity force
r = radius
m = mass
g = gravity acceleration
v = velocity

Gravity is given here as a constant : g = 9.81 m/s2.

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BETA : Cyclic : Centripetal Force 05 : Balanced Forces Kinetic Energy For Vertical Circular Motion : Beta Physics Homework Game

Description : Balanced forces and kinetic energy for vertical circular motion.

Discussion : At the balance velocity, the centripetal force and gravity force are equal when the mass is at the top of the circle. At this point the kinetic energy is at a minimum and the potential energy is at a maximum. At the bottom of the circle the kinetic energy at at a maximum and the potential energy is at a minimum. See Figure Vertical Circular Motion At the balance condition at the top of the cycle:

vt = √(r * g)
kt = m / 2 * vt2
rearranging
r = v2 / g
vt = √(2 * kt / m)

At the bottom of the circle:

kb = kt + 2 * m * g * r
vb = √(2 * kb / m)

where

vt = velocity at top of circle
vb = velocity at bottom of circle
kt = kinetic energy at top of circle
kb = kinetic energy at bottom of circle
r = radius
m = mass
g = gravity acceleration

Gravity is given here as a constant : g = 9.81 m/s2.

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BETA : Cyclic : Centripetal Force 06 : Satellite Orbital Motion : Beta Physics Homework Game

Description : Satellite earth orbit.

Discussion : Circular satellite orbits rely on the gravitational force between the satellite and the earth providing the centripetal force to keep the satellite in orbit. The centripetal force and the gravitational force are equal. See Figure Satellite Orbital Motion The satellite velocity can be calculated by:

v = √(G * M / r)
F = G * M * m / r2 = m * v2 / r
T = 2 * π * r / v
rearranging
r = G * M / v2

where

G = gravitational constant
M = mass of the earth
v = velocity
r = radius (from the center of the earth)
m = mass of satellite

The gravity constant G = 6.67E-11. The mass of the earth M = 5.98E24.

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